Question

if the origin is the centroid of a triangle whose vertices are (3,2);(-6,y);(3,-2) then y=_________
answer me ​

Answer 1

formula is

➳( x1 +x2 +x3 / 3 , y1 + y2+ y3 / 3)

pt at origin is always ( 0,0)

so,

➳2 + x + 3 / 3 = 0 and 3 + y - 2 / 3 = 0

➳5 + x = 0 and 1 + y = 0 ( as 3 × 0 = 0 )

➳x = - 5 and y = - 1

Answer 2

Step-by-step explanation:

By equating the corresponding terms we get

2+q−5=0⇒q=3

p−2+1=0⇒p=1

−3+5+r=0⇒r=−2

∴p=1,q=3,r=−2

hope it helps you