Math, asked by mpmsamalik, 11 months ago

If the origin is the centroid of the triangle PQR with vertices P (2a, 2, 6),
Q(-4, 36,-10) and R(8, 14, 2c), then find the values of a, b and c.​

Answers

Answered by malikmohaman
16

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Answered by HappiestWriter012
4

Centroid of the triangle is the point of intersection of medians of the triangle.

Given, Origin is the centroid of the triangle PQR.

So, G = ( 0, 0, 0)

Vertices of the triangle are,

P (2a, 2, 6)

Q(-4, 3b,-10)

R(8, 14, 2c)

Centroid of the triangle is given by,

 = ( \frac{2a - 4 + 8}{3}    \frac{2 + 3b + 14}{3}  \frac{6 - 10 + 2c}{3} )

So,

Comparing X coordinate

 \frac{2a - 4 + 8}{3}  = 0 \\  \\ 2a + 4 = 0 \\  \\ 2a =  - 4 \\  \\ a =  \frac{ - 4}{2}  =  - 2

Comparing Y coordinate

 \frac{2 + 3b + 14}{3}  = 0 \\  \\ 3b + 16 = 0 \\  \\ 3b =  - 16 \\  \\ b =  \frac{ - 16}{3}

Comparing Z coordinate

 \frac{6 - 10 + 2c}{3}  = 0 \\  \\  - 4 + 2c = 0 \\  \\ 2c = 4 \\  \\ c =  \frac{4}{2 }  \\  \\ c = 2

Therefore, a = - 2 , b =-16/3 , c = 2

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