Question

If the outer radii of the ends of a bucket are 5cm and 15cm and it us 24 cm high then its outer surface area is

Answer 1

Answer:

Since the bucket is in shape of a frustum we get,

R1=5 cm

R2=15 cm

H=24 cm

Slant height of cone=√(R1-R2)² +H²=26 cm

Total surface area=π(R1+R2)l +πR1²+πR2²=π[520+25+225]=22/7××770=2420 cm²

Answer 2

Answer:

c.s.a of frustum

Explanation:

=22/7(15+5)l

l=√r^2+h^2