Question

If the P.E of a particle under the action of a force is V=2x¯³-3x¯²,find the force acting on the particle.​

Answer 1

Answer:[6(X^-4  - X^-3)]

Explanation:

derivative of potential energy gives force acting on that particle.

F= -(dU/dX)

therefore -(dV/dX)=  -[(-3*2X^-4) - (-2*3X^-3)]

                              = -[(-6X^-4 + 6X^-3)]

taking negative sign inside the bracket, we get

                      F= -(dV/dX)= [(6X^-4) - (6X^-3)]

                                          =[6(X^-4  -  X^-3)]