If the P Q R S are the vertices of quadrilateral P= ( _5,_3) Q=(_4 ,_6) R = (2,_3) S= ( 1,2) find the its area
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Answer:
he quadrilateral ABCD can be divided into triangles PQS and RSQ and hence the area of the quadrilateral is the sum of the areas of the two triangles.
Area of a triangle with vertices (x
1
,y
1
) ; (x
2
,y
2
) and (x
3
,y
3
) is
∣
∣
∣
∣
∣
2
x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)
∣
∣
∣
∣
∣
Area of quadrilateral PQRS = area of triangle PQS + area of triangle RSQ
area of △PQS=
2
1
[−5(−6−2)+(−4)(2+3)+1(−3+6)]
=
2
1
[23]sq. units
area of △RSQ=
2
1
[2(2+6)+1(−6+3)+(−4)(−3−2)]
=
2
1
[33]sq. units
Area of quadrilateral PQRS = area of triangle PQS + area of triangle RSQ
=
2
1
[23]+
2
1
[33]
=
2
56
=28sq.units
solution
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