Question

If the p(x) = x^4-2x^3 +3x^2-ax+8 is divided by(x-2) it leaves a remainder 10 find the value of a

Answer 1

Step-by-step explanation:

The given polynomial is p(x) = x^ 4 – 2x^ 3 + 3x ^2 – ax +8

Given, the polynomial p(x) when divided by (x -2) leaves remainder 10.

∴ p(2) = 10 (Remainder Theorem)

⇒ (2)^4 –2( 2)^3 + 3 (2)^2 – a(2) + 8=10

⇒ 16 -16+12-2a+8=10

⇒20-2a=10

⇒-2a=10-20

⇒-2a=-10

⇒a=5

the value of a = 5