Question

If the page size for 2mb memory is 2kb then the number of higher order bits on address bus used to denote page number is
Please provide explanation

Answer 1

Given:

Page Size = 2mb

Page memory = 2kb

To find:

Number of higher order bits on address bus used to denote page number

Solution:

The problem belongs to the concept of operating system.

Since page size is 2mb and page memory is 2kb, thus -

So = 2mb/2kb = 1kb

Now 1kb = 2~10.

Thus, it means that 10 bits are there.

Answer: The number of higher order bits on address bus used to denote page number is 10.