Question

if the pair of linear equation 2x+y=8 and 6x+ky=16 have infinite solution then the value k is

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Answer 1

Answer:

$2x + y = 8 \\ 6x + ky = 16 \\ \frac{2}{6 } = \frac{1}{3} \\ \frac{1}{k} \\ \frac{8}{16} = \frac{1}{2}$

a equal not b

Step-by-step explanation:

okk

Answer 2

Answer:

Step-by-step explanation:

Given linear equations,

2x+y=8 and 6x+ky=16

so equation 1 can be taken as ax1+by1+c1=0

Here, a=2 , b=1 and c=8

and equation 2 can be taken as ax2+by2+c2=0

Here, a=6, b=k and c=16

Now comparing both the equations,

a1/a2=2/6

b1/b2=1/k

c1/c2=8/16

So, a1/a2 ≠ b1/b2 = c1/c2

       2/6  ≠  1/k     =  8/16

        1/3  ≠  1/k     =   1/2

Therefore, 1/k = 1/2

              ⇒ k=2

Answer is 2.

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