Question

if the pair of linear equation 3x-2y=11 and 6x+Ku=22 has infinitely many solutions? then k is​

Answer 1

Answer:

k=-4

Step-by-step explanation:

• 3x-2y=11-----(1)
• 6x+ky=22----(2)

If it has infinitely many solutions then

$\boxed{\tt \dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}}$

$\\ \tt{:}\Rrightarrow \dfrac{3}{6}=\dfrac{-2}{k}=\dfrac{11}{22}$

$\\ \tt{:}\Rrightarrow \dfrac{3}{6}=\dfrac{-2}{k}$

$\\ \tt{:}\Rrightarrow 3k=6(-2)$

$\\ \tt{:}\Rrightarrow 3k=-12$

$\\ \tt{:}\Rrightarrow k=\dfrac{-12}{3}$

$\\ \tt{:}\Rrightarrow k=-4$