Question

if the pair of linear equation 4x-3y=1 and kx+6y=3 have no solution then the value of k will be
(a) 8
(b) -8
(c) 7
(d) -7​

Answer 1

Answer:

-8

Step-by-step explanation:

4/k=-3/6

K=(-8)

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Answer 2

Answer: 8

Step-by-step explanation:

$\frac{a1}{a2} =\frac{b1}{b2}=\frac{c1}{c2}$

$\frac{4}{k} =\frac{3}{6}$

3k=24 (cross multiplication)

k=$\frac{24}{3}$

Therefore

k=8