Question

if the pair of linear equation x+2y=3 and 2x+4y= k coincide then the value of k​

Answer 1

Step-by-step explanation:

for coincide

a1/a2=b1/B2=c1/c2

1/2=2/4=3/k

k=6

Answer 2

Solution :-

The given pair of linear equations are

• x + 2y = 3

x + 2y - 3 = 0. ...eq( 1 )

• 2x + 4y = k

2x + 4y - k = 0. ...eq( 2 )

Compare eq( 1 ) and eq( 2 ) with

a1x + b1y + c1=0 and a2x + b2y + c2=0

Now,

It is given that the line formed by the given equation is coincide

Therefore,

We know that,

a1/a2 = b1/b2 = c1/c2

Subsitute the required values,

1/2 = 2/4 = -3/-k

Take, b1/b2 = c1/c2

2/4 = -3/ -k

2/4 = 3/k

2k = 3 * 4

2k = 12

k = 12/2

k = 6

Hence, The value of K is 6 $.$