If the pair of linear equations 2x + 3y = 7 and 2px + py = 28 -qy has infinitely many
solutions, find the values of p and q
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Answer:
since,the given pair of linear equation infinitely many solution
so, a1/a2=b1/b2=C1/c2
2/2p=3/p-q =7/28
2/2p=7/28,3/p-q=7/28
1/p=1/4., 3/p-q=1/4
p=4 , p-q=12
4-q=12
q=4-12
q=-8
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