If the pair of linear equations 2x-3y=7and2x-ky=12 are partake parallel lines then find the value of k
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2x-3y=7
2x-ky=12
firstly do
2x-3y-7=0
2x-ky-12=0
for parallel
a1/a2=b1/b2 not =c1/c2
2/2= -3/-k not=-7/-12
cross multiple
1 =3/k
solve it
k=3
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2x-ky=12
firstly do
2x-3y-7=0
2x-ky-12=0
for parallel
a1/a2=b1/b2 not =c1/c2
2/2= -3/-k not=-7/-12
cross multiple
1 =3/k
solve it
k=3
plzzz marked my answer as brainlist
thanks you
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