Question

If the pair of linear equations 3x + 4y = 6 and 4x + ky = 20 has a unique solution, then holds good. ​

Answer 1

Answer:

value of k is without 16/ 3

Step-by-step explanation:

the pair of linear equations r 3x+ 4y =6 , 4x +ky = 20

3x +4y = 6 compairing with a1x + b1y = c1

4x + ky = 20 compairing a2x + b2y = c2

a1 = 3 , b1 = 4 , c1 = 6

a2 = 4 , b2 = k , c2 = 20

a1 / a2 = 3 / 4 , b1 / b2 = 4 / k

a1 / a2 = (not) b1/b2

3/4 not equal 4/k

cross product

3×k = 4×4

k not equal to 16/3

value of k is not equal to 16/3 but any number