Math, asked by aneeshmishra108, 1 year ago

If the pair of linear equations kx + 8y = 30 and x + k^2y = 29 has unique solution,
which of the following is true in respect of k ?
a) k = 2 b) k = -2 c) k is not equal to -2 d) k is not equal to plus or minus 2

Answers

Answered by sanjeevk28012
2

Given :

The pairs of linear equations are

k x + 8 y = 30

x + k² y = 29

The equations has unique solutions

To Find :

The value of k

Solution :

The pairs of linear equations are

k x + 8 y = 30

x + k² y = 29

For unique solution of two equations a_1 x + b_1 y + c_1 = 0 and a_2 x + b_2 y +c_2 = 0

 \dfrac{a_1}{a_2}\neq  \dfrac{b_1}{b_2}

So,   By compare with given equations

\dfrac{k}{1}\neq  \dfrac{8}{k^{2} }

Or,    k³ ≠ 8

i.e     k ≠ \pm 2

Hence, The value of k for which pair of linear equation is unique is k ≠ \pm 2    Answer

Similar questions