Question

If the pair of linear equations x-y-k=0 and 6x-2y-3=0 represents an infinite solution, then the value of k is​

Answer 1

Answer:

put x = 1

Step-by-step explanation:

6×2-2y-3= 0

12-2y-3=0

9-2y= 0

-2y=0-9

-2y=-9

y=9/2

Answer 2

given,

x-y-k=0

and

6x-2y-3=0

Find

k =?

$\begin{bmatrix}x-y-k=0\\ 6x-2y-3=0\end{bmatrix}\\\mathrm{Substitute\:}x=y+k\\\begin{bmatrix}6\left(y+k\right)-2y-3=0\end{bmatrix}\\\begin{bmatrix}4y+6k-3=0\end{bmatrix}\\\mathrm{For\:}x=y+k\\\mathrm{Substitute\:}y=\frac{-6k+3}{4}\\\mathrm{Substitute\:}\\y=\frac{-6k+3}{4}\\x=\frac{-6k+3}{4}+k,\:\\y=\frac{-6k+3}{4}$