Question

if the pair of lines kx+3y+k-6=0and 3x+ky-k=0 have infinitely many solutions ,then value of k is​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

✅Here's your answer

$\frac{k}{3} = \frac{3}{k} = \frac{ - 6}{ - k} \\ \\ \frac{k}{3} = \frac{3}{k} \\ \\ {k}^{2} = 9 \\ \\ k = \sqrt{9} = 3$

Therefore the value of k is 3...

Hope it helps ✌✌....