if the parallel side of the trapezium are doubled distance between them remaining same then find the ratio of the new area of new trapezium to the area of the given trapezium
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Let the lengths of the parallel sides of the trapezium be 3acm and 4acm. Let the height of the trapezium or the distance between them be 2acm.
Area of a trapezium =
2
1
×(Sumofparallelsides)×height
=>
2
1
×(3a+4a)×2a=175cm
2
=>
2
1
×7a×2a=175
a
2
=25
=>a=5
Hence, the height of the trapezium =2a=10cm
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