Math, asked by hannahrobin2007, 2 months ago

If the parallel sides of a trapezium are 2 cm apart and their sum is 10 cm then its
area is:

Answers

Answered by EliteZeal
163

A n s w e r

 \:\:

G i v e n

 \:\:

  • Parallel sides of a trapezium are 2 cm apart

  • Sum of parallel sides is 10 cm

 \:\:

F i n d

 \:\:

  • Area of trapezium

 \:\:

S o l u t i o n

 \:\:

 \underline{\bold{\texttt{Area of trapezium :}}}

 \:\:

 \sf \dfrac { 1 } { 2 } \times (l_{1} + l_{2}) \times h ⚊⚊⚊⚊ ⓵

 \:\:

Where ,

 \:\:

 \sf l _{ 1 } = Length of 1st parallel side

 \sf l_ { 2 } = Length of 2nd parallel side

 \sf h = Distance between the parallel sides

 \:\:

 \underline{\bold{\texttt{Area of given trapezium :}}}

 \:\:

Given that , Parallel sides are 2 cm apart and Sum of parallel sides is 10 cm

 \:\:

Thus ,

 \:\:

  •  \sf l _{ 1 } + l _{ 2 } = 10

  •  \sf h = 2

 \:\:

Putting the above values in ⓵

 \:\:

 \sf \dfrac { 1 } { 2 } \times (l_{1} + l_{2}) \times h

 \:\:

 \sf \dfrac { 1 } { 2 } \times (10) \times 2

 \:\:

➨ 10 sq. cm.

 \:\:

  • Hence the area of trapezium is 10 sq. cm.

 \:\:

Additional information

 \:\:

Perimeter of trapezium

 \:\:

  • a + b + c + d

 \:\:

Where ,

 \:\:

➻ a = Length of 1st side

➻ b = Length of 2nd side

➻ c = Length of 3rd side

➻ d = Length of 4th side

 \:\:

Properties of trapezium

 \:\:

  • The sum of all the four angles of the trapezium is equal to 360°

  • A trapezium has two parallel sides and two non-parallel sides

  • The diagonals of regular trapezium bisect each other

  • The length of the mid-segment is equal to half the sum of the parallel bases, in a trapezium

Answered by Anonymous
13

\large{\underbrace{\sf{\orange{required \: solution:}}}}

given that,

  • The parallel sides of a trapezium are 2 cm apart.
  • Their sum is 10 cm

☯️we need to find the area of the trapezium.

_____________________

according to the question,

 \bf {required \: formulae : }

 {:  \implies  \bf \underline \blue{ \frac{1}{2} \times sum \: of \: parallel \: sides  \times h }}

  • sum of parallel sides = 10 (given)

  • h = height = distance between them = 2cm

 :  \implies \sf \frac{1}{2}  \times (10) \times 2 \\   \\ :  \implies  \sf\:{5 \times 2}   \\  \\  \:  \:  \:  \:  \:  \: :   \implies \bf \underline \green{\:  {10cm}^{2} }

hence , The area of the trapezium is 10cm²

_____________________

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