Question

If the parallel sides of an isosceles trapezium is 16cm and 26cm,and each of the unparalleled sides are 13cm,then the altitude of the trapezium is​

Answer 1

follow the steps and carefully look at the attached diagram for better understanding

when you say that each of the unparallel sides are equal = 13 cm then surely this has to be a isosceles trapezium

Now in ΔAEC you can see that the it is a right angled triangle and thus using Pythagoras Theorem :-

AC² = EC² + + AE²

on putting the values you get

AE² = (13)²-(5)² = 169-25 = 144

AE = √(144) = 12

Thus the altitude of the trapezium is 12 cm

If you really feel the it helped you then don't forget to mark the answer as the BRAINLIEST !

Thank You very much