Math, asked by mahimishra94, 10 months ago

if the parallel sides of atrapezium are 22 cm and 38 cm, and its area is 585 cm square, find the height of the trapezium​

Answers

Answered by neeraj1251
28

Answer:

19.5 cm

Step-by-step explanation:

Given, Area of trapezium=585 cm^2

Parallel sides= 22cm and 38cm

Area of trapezium= 585

 \frac{1}{2}(a + b) \times h = 585

 \frac{1}{2} (22 + 38) \times h = 585

 \frac{60}{2}  \times h = 585

30h=585

h=585/30

h=19.5 cm

Answered by nikita3475
13

Answer:

answer is 19.5

Step-by-step explanation:

let the height of the given trapezium be x cm.

Then,the area of trapezium be 1/2(sum of parallel side)×height

=1/2(22+38)×x cm=585 cm square

=1/2×60=585 cm square

=30x=585cm2

=x=585÷30

therefore,x=19.5

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