if the particle is moving along a straight line given by the relation x=2-3t+4tcube where s is in cms and t is in sec it's average velocity during third sec is
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Answer:
Displacement of particle is given by:
x=2−3t+4t
3
Velocity, v=
dt
dx
=−3+12t
2
At t = 3 s
v=−3+12×9
v=105cm/s.
i hope it's help to you
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