Question

If the particle is moving along a straight line given by the relation s=2-3t+4t^3 where s is in cm.,and t in sec.,it's average velocity during the third sec is

Answer 1

Therefore the average velocity during 3rd sec is 33 m/s.

Given : The particle is moving along a straight line given by the relation s = 2 - 3t + 4t³ where s is in cm.,and t in sec.

To find : here s = 2 - 3t + 4t³

differentiating w.r.t time we get,

ds/dt = v(t) = -3 + 12t² ......(1)

using formula,

$\textbf{average velocity}=\frac{1}{t_2-t_1}\int\limits^{t_2}_{t_1}v(t)dt$

here t₂ = 3s , t₁ = 0s

so, average velocity = $\frac{1}{3-0}\int\limits^3_0{(-3+12t^2)}\,dt$

= $\frac{1}{3}\left[-3t+4t^3\right]^3_0$

= 1/3 [-3 × 3 + 4 × 3³ ]

= -3 + 4 × 3²

= -3 + 36

= 33 m/s

Therefore the average velocity during 3rd sec is 33 m/s.

Answer 2

Answer:

33m/s

Explanation:

you should no average velocity formula