Question

If the path is represented by (x)2+2x-3,then its zeroes are? (1 Point) (-3, 1) (3,-1) (2,-3) (-2, 3)

Answer 1

Answer:

(-3,1)

Step-by-step explanation:

x^2+2x-3=0

x^2+(3-1)x-3=0

x^2+3x-x-3=0

x(x+3)-1(x+3)=0

(x+3)(x-1)=0

so, x=-3,x=1

now .zeroes of this equation are -3,1 or (-3,1)