Question

If the path is represented by x2 +2x-3, then the zeroes are(a) -1 and 3 (b) 1 and -3 (d) 1 and 0 (d) None of these​

Answer 1

Answer:

b

Step-by-step explanation:

x^2+2x+3=0

x^2+(3-1)x-3=0

x^2+3x-x-3=0

x(x+3)-1(x+3)=0

(x-1)(x+3)=0

x=1,x=-3==theae are the zeroes of this equation

Answer 2

Given: The path is represented by x² +2x - 3.

To find: The zeroes or the values of x.

Solution:

• To find the values of x, we factorize the quadratic equation by splitting the middle term.
• To do so, we first multiply the x² term and the constant and then, we find the suitable factors to split the middle term.

       $x^{2} + 2x - 3 = x^{2} +3x - x - 3$

• Now, we take out the common terms so that we are left with the factors.

       $x^{2} +3x - x - 3 = x (x + 3) -1 (x + 3)$

       $(x+3)(x-1)$

• Now, we equate the factors to zero in order to find the values of x.

       $x -1 = 0$

       $x=1$

       $x+3=0$

       $x=-3$

Therefore, the values of x are 1 and -3.