If the path of a javelin is represented by x2+x –20. Then its zeroes are
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Answered by
2
Range of the projectile R=
g
u
2
sin2θ
∴ Range is maximum when sin2θ=1
⟹ θ=45
o
Thus maximum range is achieved when θ=45
o
and thus it depends on the angle of projection.
Also, in javelin throw, in order to throw the javelin to maximum far distance the athlete has to throw it at an exact angle of 45
o
with the horizontal.
Hence both the assertion and the reason are incorrect.
Answered by
0
Answer:
x² + x - 20
= x² + 5x - 4x - 20
= x(x + 5) - 4(x + 5)
x-4=0
→x=-4
x+5=0
→x=-5
zeroes are 4 and -5
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