If the percentage change in the radius of a sphere is 2 % . Then what is the percentage change in its surface area
Answers
Answer:
Given that the radius of a sphere is doubled.
To find out; Percentage increase in its surface area.
Let initial radius =r
0
We know that the surface area of a sphere =4πr
2
.
Hence, initial surface area =4πr
0
2
Now, final radius =2r
0
Hence, final surface area =4π(2r
0
)
2
=4.4πr
0
2
=16πr
0
2
Hence, increase in surface area =16πr
0
2
−4πr
0
2
=12πr
0
2
So, percentage increase in surface area =
4πr
0
2
12πr
0
2
×100=300%.
Hence, if the radius of a sphere is doubled, its surface area increases by 300%.
Explanation:
Explanation:
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IF PERCENTAGE CHANGE IN RADIUS IS 2% THEN THE PERCENTAGE CHANGE IN THE SURFACE AREA IS 4%.
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