If the percentage error in calculating the radius
of the sphere is 2%, what will be the percentage
error in calculating the volume? (SAY 2013)
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Step-by-step explanation:
dr/r*100=2
dr/r=2/100
V=4/3πr^3
log on both sides
logV= log 4/3+ log π+3 log r
differentiate on both sides
dv/v=3*dr/r
dv/v=6/100
percentage error in volume =dv/v*100
=6/100*100 =6 percent
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