Question

If the percentage error in calculating the radius of the sphere is 2% what will be the percentage error in calculating the volume?

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Secondary SchoolPhysics 5+3 pts

The error in the measurement of the radius of a sphere is 2% .What will be the error in the calculation of its surface area?

[hint:Surface areas=4πr² ,∆A/A= 2∆r/r]

Report by Reetikarajput 18.05.2018

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Harshkumar7173 · Helping Hand

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Given, error in radius of sphere is 2%

it means ∆r = 2%

now, surface area of sphere is

A = 4πr^2

∆A/A = (2×∆r/r)

∆A/A = 2×2/100 = 0.04

∆A/A×100 = 0.04×100 = 4℅

it means % error in surface area of its measurement is 4%