Physics, asked by yashwanth9870, 8 months ago

if the percentage error in mass and volume is 1% and 3%,the percentage error in density is

Answers

Answered by nihadjahan64
2

Answer:

4%

Explanation:

density=mass÷volume

%error in density=1+3

=4%

Answered by nirman95
3

Given:

The percentage error in mass and volume is 1% and 3%.

To find:

% error in density.

Calculation:

Density is define as the mass per unit volume for a substance.

 \boxed{ \sf{ \rho =  \dfrac{m}{ V} }}

Now , for small errors in mass and volume (< 6%) , we can say that:

 \rm{ \therefore \dfrac{\Delta \rho}{ \rho}  =  \dfrac{\Delta m}{m}  +  \dfrac{\Delta V}{ V} }

Putting available values:

 \rm{  =  &gt;  \dfrac{\Delta \rho}{ \rho}  =  1\%  +  3\%}

 \rm{  =  &gt;  \dfrac{\Delta \rho}{ \rho}  = 4\%}

So, max relative error in density = 4%.

  • This method can be used only when the errors in individual quantities is less than 6%. This is because it is an approximated method.

  • If the error is higher , then you have to differentiate and follow that procedure.
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