If the percentage error in radius of a spehere is 2% the percentage error in its volume is ____.
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Percentage error in radius is given as 2% i.e.
r
Δr
×100=2 %
Volume of sphere V=
3
4π
r
3
Percentage error in volume
V
ΔV
×100=3×
r
Δr
×100=3×2=6 %
r
Δr
×100=2 %
Volume of sphere V=
3
4π
r
3
Percentage error in volume
V
ΔV
×100=3×
r
Δr
×100=3×2=6 %
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