Physics, asked by LaluprasadSharma124, 4 months ago

If the percentage error in radius of a spehere is 2% the percentage error in its volume is ____.​

Answers

Answered by jagruthichihnitha
1
Percentage error in radius is given as 2% i.e.
r
Δr

×100=2 %
Volume of sphere V=
3


r
3

Percentage error in volume
V
ΔV

×100=3×
r
Δr

×100=3×2=6 %
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