Question

If the percentage error in the measurement of a side of the cube is 2% the % errors respectively in its volume and area are

Answer 1

Answer:

8 and 4

Explanation:

volume of cube is a^3 and area is a^2 so that error are 8% and 4% Respectively...

Answer 2

Given:

Percentage error in measurement of side of cube = 2 %

i.e., (Δa/a) × 100 = 2 %

To Find:

Percentage error in the volume and area of cube.

Calculation:

- Area of cube, A = a²

⇒ Percent error in area is given by

(ΔA/A) × 100 =2 (Δa/a) × 100

⇒ (ΔA/A) × 100 = 2 × 2

⇒ (ΔA/A) × 100 = 4 %

- Volume of cube, V = a³

⇒ Percent error in volume is given by

(ΔV/V) × 100 = 3 (Δa/a) × 100

⇒ (ΔV/V) × 100 = 3 × 2

⇒ (ΔV/V) × 100 = 6 %

- Thus, % error in area and volume is 4 % and 6 % respectively.