If the percentage error in the measurement of radius of sphere is 3%, then percentage error in measurement of it's volume is
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Answered by
56
Answer:
2*3+0.09 = 6.09
6.09 +3 + 0.1827 = 9.2727% (Ans.)
Answered by
2
Answer:
percentage error in measurement of it's volume is 9%
Explanation:
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