If the percentage error in the measurement of surface area if solid sphere is 4 % then percentage error in the measurement of radius and volume
Answers
Answer:
% Error in Radius = 2%
% Error in Volume = 6%
Step-by-step explanation:
In the question,
The percentage error in the measurement of Surface Area of solid = 4%
So,
We know that,
Surface Area of Sphere is = 4πr²
Now,
Therefore, the percentage error in the measurement of radius is 2%.
Now,
Volume of Sphere is,
Therefore,
Therefore, the Percent Error in the measurement of Volume is 6%.
Given: If the percentage error in the measurement of surface area if solid sphere is 4 %.
To find: The percentage error in the measurement of radius and volume.
Solution: The percentage error in the measurement of radius and volume is 2% and 6%, respectively.
The surface area of a sphere can be given by the following formula.
Here, S is the surface area and r is the radius of the sphere. Since the surface area is directly proportional to the radius of the sphere, the percentage error can be written as follows.
Thus, the percentage error in the measurement of radius is 2%. Now, the volume of a sphere can be found using the following formula.
Since the volume is directly proportional to the cube of the radius of the sphere, the percentage error can be written as follows.
Thus, the percentage error in the measurement of volume is 6%.
Therefore, the percentage error in the measurement of radius and volume is 2% and 6%, respectively.