If the percentage error in the measurement of voltage is 5% and that in current 2% ,then what is tha percentage error in power
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According to Ohm's law,
V = IR
Where R is resistance of wirr, I is current flows through wire, V is voltage or potential difference.
For finding error in R, we have, AR/R = A1/1 +AVN Means, % error in R=% error in I+% error in V
Here given, % error in 1 = 2% % error in V = 3 %
:: % error in R = 2% + 3% = 5%
Here, answer is 5%
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