Question

If the percentage of water of crystallization in MgSO4.x H2O is 13%, what is the value of x?

Answer 1

Answer:

⇒ Mass of MgSO₄ = 24 + 32 + 64 = 120 g

⇒ Hence mass of MgSO₄.x H₂O = 120 + 18x

⇒ Now, it is given that 13% is water….

⇔ 13 % = ( mass of water ) / ( mass of total compound )

⇒  13/100 = (18x)/(18x + 120)

⇒ 1800x = 13(18x + 120)

⇒ 1800x = 234x + 1560

⇒ 1566x = 1560

⇒ x ≈ 1

Hence The compound is MgSO₄ . H₂O

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