Question

if the percentage of water of crystallization in MgSO4.x.H2O is 13% , what is the value of x ?

Answer 1

hope it will help you

Answer 2

Hi friend,

# X= 1

Solution :-

➡Mass of MgSo4 = 120.366 g/mol

Mass of H20 = 18.015 g/mol

➡So, we put the formula

% of crystalization = Mass of water of crystalization / mass of compound*100

Given 13% of crystalization

Therefore,

13 = 18.015x/ 120.366 + 18.015x × 100

Or , X = 1 ( proved )

...i hope it helps you
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