if the percentage of water of crystallization in MgSO4.x.H2O is 13% , what is the value of x ?
Anonymous:
is x = 9.
i need confidence so please reply
NO
the answer could be either of 1/4/5/7
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Answered by
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Answered by
85
Hi friend,
# X= 1
Solution :-
➡Mass of MgSo4 = 120.366 g/mol
Mass of H20 = 18.015 g/mol
➡So, we put the formula
% of crystalization = Mass of water of crystalization / mass of compound*100
Given 13% of crystalization
Therefore,
13 = 18.015x/ 120.366 + 18.015x × 100
Or , X = 1 ( proved )
...i hope it helps you
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Mark me as a brainliest✌.
# X= 1
Solution :-
➡Mass of MgSo4 = 120.366 g/mol
Mass of H20 = 18.015 g/mol
➡So, we put the formula
% of crystalization = Mass of water of crystalization / mass of compound*100
Given 13% of crystalization
Therefore,
13 = 18.015x/ 120.366 + 18.015x × 100
Or , X = 1 ( proved )
...i hope it helps you
_____________________________
Mark me as a brainliest✌.
correct
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