If the perimeter and base of an isosceles triangle are 11 cm and 5 cm respectively, then its area is
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Given : perimeter and base of an isosceles triangle are 11 cm and 5 cm respectively
To find : Area of Triangle
Solution:
perimeter of isosceles triangle = 11 cm
Base = 5 cm
Equal Sides = a
=> 11 = 5 + a + a
=> 2a = 6
=> a = 3
Sides of Triangle are 3 , 3 & 5
s = (3 + 3 + 5)/2 = 11/2
Using heron's formula
Area of triangle = √(11/2)(11/2 -5)(11/2 - 3)(11/2 - 3)
= (1/4) √11(1)(5)(5)
= (5/4)√11
= 4.15 cm²
Area = 4.15 cm²
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