If the perimeter of a certain sector is 10 units and radius of the circle is 3 units , find the area of sector ?
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Given,
Perimeter of a sector = 10 units
Length of arc = 10 units - 6 units = 4 units.
Radius of circle = 3 units.
Area of sector = ?
Fitst find the circumference of circle.
Circumference of circle = 2 π r
= 2 × ( 22/7 ) × 3
= ( 132 / 7 ) Units.
Now,
Central angle / 360°=length of arc /Circumference of circle
●/ 360° = 4 / ( 132 / 7 )
●/ 360° = 28 / 132
● = ( 28 × 360° ) / 132
● = ( 14 × 360° ) / 66
● = ( 14 × 180° ) / 33
● = ( 14 × 60° ) / 11
● = 840° / 11.
Area of circle = πr^2
= ( 22 / 7 ) × ( 3 units )^2
= ( 22 / 7 ) × 9 units^2
= ( 198 / 7 ) units^2
Area of sector = ( ● / 360° ) × ar. of circle
= { ( 840° / 11 ) / 360° } × ( 198 / 7 ) unit^2
= { 840° / ( 360° × 11 ) } × ( 198 / 7 ) unit^2
= { 7 / 33 } × ( 198 / 7 ) unit^2
= ( 198 / 33 ) unit^2
= 6 unit^2.
Perimeter of a sector = 10 units
Length of arc = 10 units - 6 units = 4 units.
Radius of circle = 3 units.
Area of sector = ?
Fitst find the circumference of circle.
Circumference of circle = 2 π r
= 2 × ( 22/7 ) × 3
= ( 132 / 7 ) Units.
Now,
Central angle / 360°=length of arc /Circumference of circle
●/ 360° = 4 / ( 132 / 7 )
●/ 360° = 28 / 132
● = ( 28 × 360° ) / 132
● = ( 14 × 360° ) / 66
● = ( 14 × 180° ) / 33
● = ( 14 × 60° ) / 11
● = 840° / 11.
Area of circle = πr^2
= ( 22 / 7 ) × ( 3 units )^2
= ( 22 / 7 ) × 9 units^2
= ( 198 / 7 ) units^2
Area of sector = ( ● / 360° ) × ar. of circle
= { ( 840° / 11 ) / 360° } × ( 198 / 7 ) unit^2
= { 840° / ( 360° × 11 ) } × ( 198 / 7 ) unit^2
= { 7 / 33 } × ( 198 / 7 ) unit^2
= ( 198 / 33 ) unit^2
= 6 unit^2.
Anonymous:
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Answered by
14
Radius of circle = 3 units
Perimeter of an arc = 10 units
Length of that arc = Perimeter of that arc - 2 × Radius of that circle
= 10 units - 2 × 3 units
= 10 units - 6 units = 4 units.
Perimeter of circle = 2πr
= 2 ( 22/7 ) 3 unit
= ( 132 / 7 ) unit
Area of circle = πr²
= ( 22/7 ) × ( 3 units )²
= ( 22/7 ) × 9 unit²
= ( 198 / 7 ) unit²
To find the area of a sector we have a formula,
Area of a sector = ( Central angle / 360° ) × Area of circle
Now,
Let the central angle is α.
⇒ ( 360° / α ) = Perimeter of circle ÷ Length of Arc
⇒ ( 360° / α ) = ( 132 / 7 ) unit ÷ 4 unit
⇒ ( 360° / α ) = ( 132 / 7 × 4 )
⇒ ( 360° / α ) = ( 33 / 7 )
⇒ α = ( 360° × 7 ) ÷ 33
⇒ α = ( 120° × 7 ) ÷ 11
∴ α = 840° / 11.
Now,
Area of sector = ( α / 360° ) × Area of circle
= { ( 840° / 11 ) ÷ 360° } × ( 198 / 7 ) unit²
= { 840° / 11 × 360° } × ( 198 / 7 ) unit²
= (7 / 11 × 3 ) × ( 198 / 7 ) unit²
= ( 7 / 33 ) × ( 198 / 7 ) unit²
= ( 198 / 33 ) unit²
= 6 unit²
The required answer is 6 unit².
Hope it helps !!
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