If the perimeter of a parallelogram is 140 m and the distance between the opposite sides are 7 m and its area is 210 sq m find the length of the adjacent sides
Answers
Answered by
7
let the base be x area of parallelogram = b×h = 210= x× 7=210 so x= 210÷7=30 then let the adjacent side be y so y + y +30+30= 140 =2y+60=140 =2y=140-60 2y = 80=y= 80÷2=40m
Anonymous:
becoz 7m is height
Answered by
7
heya buddy
here is your answer
Perimeter of parallelogram is 140m
distance between the opposite sides is 7m
=> height of parallelogram is 7m
and also , area is 210 sq m
=> base = area / height
base = 210/7 = 30m
there fore length of base of //gm is 30m
=> 2 opposite sides of //gm are 30m,30m
as the base of the parallelogram is also a side of the parallelogram
remaining 2 sides = Perimeter of parallelogram - length of 2 sides
= 140 - 60 = 80m
=> length of one side = 80/2 = 40
there fore length of 2 adjacent sides are 40m , 30m
here is your answer
Perimeter of parallelogram is 140m
distance between the opposite sides is 7m
=> height of parallelogram is 7m
and also , area is 210 sq m
=> base = area / height
base = 210/7 = 30m
there fore length of base of //gm is 30m
=> 2 opposite sides of //gm are 30m,30m
as the base of the parallelogram is also a side of the parallelogram
remaining 2 sides = Perimeter of parallelogram - length of 2 sides
= 140 - 60 = 80m
=> length of one side = 80/2 = 40
there fore length of 2 adjacent sides are 40m , 30m
Similar questions