if the perimeter of a protractor is 72 cm, calculate its area.
Answers
Answered by
6
As protractor is a semi circle so it's perimeter will be πr
72=22/7×r
72×7/22=,r
36×7/11=r
252/11=r
22.9=r
area=1/2πr^2
1/2×22/7×(22.9)^2
1/2×22/7×524.41
824.07Ans
Hope this will help you.
72=22/7×r
72×7/22=,r
36×7/11=r
252/11=r
22.9=r
area=1/2πr^2
1/2×22/7×(22.9)^2
1/2×22/7×524.41
824.07Ans
Hope this will help you.
Answered by
5
Since a protractor is a semicircle
Hence, Perimeter of the semicircle = 72cm
πr = 72
r = 252/11
Now, Area of the semicircle = πr^2/2
= 22*252*252/7*11*11*2
= 9076/11
=825 cm^2
Hence, Perimeter of the semicircle = 72cm
πr = 72
r = 252/11
Now, Area of the semicircle = πr^2/2
= 22*252*252/7*11*11*2
= 9076/11
=825 cm^2
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