Question

if the perimeter of a rectangale is 38 meter ,find it's breth​

Answer 1

Step-by-step explanation:

Given data :- The perimeter of a rectangle P =38 meter. If the length is 5 meter less than twice it's width.

Find out :- The dimensions of the rectangle =?

Let assume that the length of the rectangle L = (2x -5)m

And the width of the rectangle W = x meter

Now Perimeter P = 2(L+W)

38 = [2{x+(2x-5)}]

3x-5=19

3x= 24 , x = (24/3)= 8 meter

So the required width of the Rectangle W = 8 meter answer .

And the required length of the rectangle L = (2x-5) = (2×8–5) = 11 meter answer