Question

if the perimeter of a rectangle is 11cm and its width is 2 2/3 cm, then the length of the rectangle is​

Answer 1

Answer:

Perimeter = 2•Length + 2•Width

Length = Width +3cm

Therefore we can say,

P = 2(W+3) + 2(W)

After using the distributive property, we get

P = 2W + 6 + 2W → P = 4W +6

Substitute 11cm with P next,

11 = 4W + 6 → Subtract 6 from both sides→ 5 = 4W

Now divide both sides by 4

(5/4) = (4W/4) → So the width is equal to 1.25cm

Now we can find length by substituting 1.25 for W

L = W + 3 → L = 1.25 + 3 and so.. Length equals 4.25cm.

Answer 2

Answer:

perimeter of a triangle=2(a+b)

width =2⅔cm

let the length be =x

2(2⅔+x)=11cm

2(8/3+x)=11cm

16/3+2x=11cm

16+6x/3=11cm

16+6x=11×3

16+6x=33

6x=33-16

6x=17

x=17/6cm

Step-by-step explanation:

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