If the perimeter of a rectangle is 132m, then what is the sum of its dimensions?Required to answer. Single choice.
66 m
132 m
120 m
Cannot be determined
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Given:
perimeter of rectangle = 132 m
Find:
sum of dimensions ( l + b )
perimeter of rectangle = 2 ( l + b )
132 = 2 ( l + b )
132/2 = ( l + b )
66 = ( l + b )
l + b = 66 m
sum of dimensions = 66 m
Note :
l = lenght of rectangle .
b = breadth of rectangle .
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