Math, asked by khushbur600, 4 months ago

If the perimeter of a rectangle is 132m, then what is the sum of its dimensions?Required to answer. Single choice.




66 m

132 m

120 m

Cannot be determined


Answers

Answered by PhoenixAnish
3

Given:

perimeter of rectangle = 132 m

Find:

sum of dimensions ( l + b )

perimeter of rectangle = 2 ( l + b )

132 = 2 ( l + b )

132/2 = ( l + b )

66 = ( l + b )

l + b = 66 m

sum of dimensions = 66 m

Note :

l = lenght of rectangle .

b = breadth of rectangle .

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