Question

If the perimeter of a rectangle is 180 m and difference between the length and the breadth is 8m ,what is the area of the rectangle​

Answer 1

Answer:

2009 m^2

Step-by-step explanation:

Perimeter = 180 m

(perimeter of rectangle = 2(l+b))

=> 2(l+b) = 180 ________(i)

as difference between l and b is 8

or l - b = 8

or l = 8 + b

put the value of l in equation (i)

=> 2(8+b + b) = 180

=> 2 (8 + 2b) =180

=> 8 + 2b = 180/2

=> 2b = 90-8

=> b = 82/2

=> b = 41

as l = 8 + b

or l = 8 + 41

or l = 49

therefore area of rectangle = l×b

or

41 × 49

or 2009 m^2

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Answer 2

Answer:

l=49 ,b=41

area of rectangle =49×41

=2009 answer.........

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