if the perimeter of a rectangle is 180 meters and the difference between the length and the breadth is 8 meters what is the area of the rectangle
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Let the length be l
Breadth be b
A/Q
perimeter =180m
=》 2(l+b)=180m
=》l+b=180/2m
=》l+b=90m ........(1)
Again ,
=》 l - b =8m.......(2)
(1) - (2) =》l+b+l-b=90-8m
=》2l=82m
<》l=41m
putting the value of l =41 in quation (1)
l+b=90m
41+b=90m
b =90-41= 49m
Therefore area is l×b=41×49=2009m sq.
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