if the perimeter of a rectangle is 180 meters and the difference between the length and the breadth is 8 meters what is the area of the rectangle
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Answered by
0
Perimeter = 2 (l+b) =180
So, l + b = 90---------1
Difference = l- b = 8---------------2
Add 1 & 2
=>l+b+l-b = 98
=> 2l =98
=> l = 49
And b = 49-8 = 41
Terefore ,
Area = lb = 49×41 =2009 m²
So, l + b = 90---------1
Difference = l- b = 8---------------2
Add 1 & 2
=>l+b+l-b = 98
=> 2l =98
=> l = 49
And b = 49-8 = 41
Terefore ,
Area = lb = 49×41 =2009 m²
Answered by
0
Given, 2(L+B)=180m =>L+B=90-----(i)
and L-B=8-----(II)
Solving (i)&(ii) 2L=98 =>L=49&B=41
Now, area of rectangle=L*B=49*41=2009m^2
Hope it helps, if any doubt plz comment, plz mark as brainliest
and L-B=8-----(II)
Solving (i)&(ii) 2L=98 =>L=49&B=41
Now, area of rectangle=L*B=49*41=2009m^2
Hope it helps, if any doubt plz comment, plz mark as brainliest
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