Question

if the perimeter of a rectangle is 24 cm and its area is 20 sq.cm.half of the perimeter =?​

Answer 1

Step-by-step explanation:

half of the perimeter = 24/2 =12

Answer 2

Answer:

6 + 2(sqrrt(3)) and 6 - 2(sqrrt(3)) or approximately 9.4641 and 2.5359

Let x = the length and let y = the width

Because the perimeter is 24 I know: 2x + 2y =24

Because the area is 24 I know: xy =24

Isolate x in the 1st equation and substitute this new value of x in the 2nd equation

2x+2y = 24:subtract 2y on both sides 2x = -2y + 24:Divide both sides by 2: x = -y + 12

(-y + 12) (y) = 24 => -(y^2) + 12y =24 subtract -(y^2) and 12 y from both sides

0 = y^2 - 12y +24 Use the Quadratic Formula [12 +/- Sqrrt(144–4(1)(24)]/2

[12 +/- sqrrt(48)]/2 = 6 +/- 2(sqrrt(3))

Sides are 6 + 2(sqrrt(3)) and 6 - 2(sqrrt(3)) or approximately 9.4641 and 2.5359