Question

if the perimeter of a rectangle is 48 cm and its breadth is 10 cm. Find the
length of the rectangle.​

Answer 1

Answer:

perimeter is 2*(l+b)

2*(l+10)=48

l+10= 24

l= 14cm

hope it helps you.

Answer 2

Answer:

Length of rectangle is 14 cm.

Step-by-step explanation:

Given that:

• Perimeter of rectangle is 48 cm.
• Breadth in rectangle is 10 cm

To find:

• Length of rectangle

Formula to know:-

Perimeter of rectangle = 2(l+b)

Where l is length of rectangle,b is breadth of rectangle.

Solution:-

Let the length of rectangle be x

so, Finding the length

Perimeter of rectangle = 2(l+b)

=> 48cm = 2(10cm+x)

=> 48cm = 20cm+2x

=> 48cm-20cm = 2x

=> 28 = 2x

=> x =$\fbox{${\frac{28}{2}}$}$

=> x = 14 cm

so, the length of rectangle is 14 cm

Known more:-

Area of square is S²

where "S" is side of square.

---------------- » «» « ---------------

Area of rectangle = l+b

where l = length

b = breadth of rectangle

---------------- » «» « ----------------

Area of rhombus is ½ d1 d2

where d1,d2 are diagonal of rhombus.

${}^{hope \: its \: help \: you.}$