Question

if the perimeter of a rectangle is 60 cm and the width is half the length of the rectangle,what is the length of the rectangle?​

Answer 1

ANSWER

10 cm

STEP BY STEP

Let length = let length = 2 x

and breadth x

perimeter of rectangle = 2 (1 + b )

60 = 2 (2x+x)

60 / 2 = 3x

30/3 = x

10=x

1=2x10=20 cm

b = 10 cm

thank you

Answer 2

$\sf\huge\bold{Solution}$

Given

Perimeter of Rectangle is 60cm.

Width/breadth is half of length

To Find

Length of the Rectangle

Let the length of the rectangle be 'x' cm

Given that breadth/width is half the length of the rectangle so , breadth will be $\bold{\dfrac{x}{2}}$cm

Perimeter of Rectangle is 60cm

Perimeter of Rectangle=2(length+breadth)

$\sf \longmapsto 60 = 2\bigg(x + \dfrac{x}{2}\bigg )$

$\sf \longmapsto 60 = 2\bigg( \dfrac{2x + x}{2}\bigg )$

$\sf \longmapsto 60 = 2\bigg( \dfrac{3x}{2} \bigg)$

$\sf \longmapsto 30 = \dfrac{3x}{2}$

$\sf \longmapsto 3x = 60$

$\sf \longmapsto \bold{x = 20}$

Now ,we find the length of the Rectangle is 20cm

Breadth of Rectangle is $\sf \dfrac{x}{2} = \dfrac{20}{2} = 10$

Length=20cm

Breadth =10cm

Check

$\sf \longmapsto 2(length + breadth)$

$\sf \longmapsto 2(20 + 10) = 2 \times 30 = 60$